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    EOF_IN);
    SELECT(INSTRUC.A);
    WHEN('1') DO;
    Z1 +-= Z1;
    ITERATE LOOP;
    END;
    WHEN('3') DO;
    Z3 = Z3+1;
    LEAVE LOOP;
    END;
    WHEN('2') DO;
    Z2 = Z2+1;
    WRITE FILE(DDOUT) FROM(INSTRUC);
    END;
    OTHER DO;
    ZO = ZO+1;
    PUT SKIP LIST(INSTRUC.A);
    END;
    END;/*select*/
    READ FILE(DDIN) INTO(INSTRUC);
    END ;/*loop*/
    A. The code does not fulfill the requirement because the last record with '2' in the first byte will be written twice to the output dataset.
    B. The code does not fulfill the requirement because the program will loop infinitely.
    C. The code does not fulfill the requirement because not all records with '2' in the first byte will be written to the output dataset.
    D. The code fulfills the requirement.
    Answer: B

    NEW QUESTION: 2

    A. Option D
    B. Option C
    C. Option B
    D. Option A
    Answer: B,D

    NEW QUESTION: 3
    An entity prepares financial statements to 31 December each year. The following data applies:
    1 December 20X0
    * The entity purchased some inventory for $400,000.
    * In order to protect the inventory against adverse changes in fair value the entity entered into a futures contract to sell the inventory for a fixed price on 31 January 20X1.
    * The entity designated this contract as a fair value hedge of the value of the inventory.
    31 December 20X0
    * The inventory had a fair value of $480,000 and the futures contract had a fair value of $75,000 (a financial liability).
    What will be the impact on the statement of profit or loss and other comprehensive income for the year ended 31 December 20X0 in respect of the change in the value of the inventory and the futures contract?
    A. A loss of $75,000 will be recognised in other comprehensive income.
    B. A net gain of $5,000 will be recognised in other comprehensive income.
    C. A net gain of $5,000 will be recognised in profit or loss.
    D. A loss of $75,000 will be recognised in profit or loss.
    Answer: C

    NEW QUESTION: 4
    Refer to the exhibit.

    An administrator supports a RAP at a branch office shown in the exhibit. The company has one Mobility
    Controller (MC) at the Primary DMZ site and one at the Secondary DMZ site. The RAP is configured to
    connect to only the MC at the Primary DMZ site. A network outage with the ISP at the Primary DMZ site
    causes the RAP to reboot. Upon reboot, the RAP cannot build a tunnel to the Secondary DMZ site MC
    because the administrator forgot to add the Second LMS IP address to the AP Group configuration. Once the
    RAP can successfully connect, the administrator can add the Secondary DMZ MC as a backup LMS to fix the
    AP Group.
    What should the administrator implement to allow the RAP to connect to the MC at the Secondary DMZ site
    while the outage at the primary site persists?
    A. Dynamic discovery through DHCP Option 43
    B. Dynamic discovery through multicast ADP
    C. Dynamic discovery through DHCP Option 60
    D. Static configuration from apboot mode
    Answer: A


     



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