sMiame).-2)='a';
B. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')oM AND SUBSTR(cust_first_name. -2, 1'a';
C. SELECT custfirstname
FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name. -2, 1)=a;
D. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')IS NOT NULL AND SUBSTR(cust_first_name. 1 .-2)='a';
Answer: C

Lloydmichaux, Dumps, Braindumps, PDF, Test Engine, Practice Test"> sMiame).-2)='a';
B. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')oM AND SUBSTR(cust_first_name. -2, 1'a';
C. SELECT custfirstname
FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name. -2, 1)=a;
D. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')IS NOT NULL AND SUBSTR(cust_first_name. 1 .-2)='a';
Answer: C

Lloydmichaux C-DS-42 Dumps PDF + Test Engine available. 100% SAP Certified Application Associate - Data Integration with SAP Data Services 4.2 - Sterling Or Passing Guarantee. "> fii-<br/>sMiame).-2)='a';<br/><strong>B.</strong> SELECT custfirstname FROM customers<br/>WHERE INSTR(cust_first_name. 'e')oM AND SUBSTR(cust_first_name. -2, 1'a';<br/><strong>C.</strong> SELECT custfirstname<br/>FROM customers<br/>WHERE INSTR(cust_first_name, 'e')<>0 AND<br/>SUBSTR(cust_first_name. -2, 1)=a;<br/><strong>D.</strong> SELECT custfirstname FROM customers<br/>WHERE INSTR(cust_first_name. 'e')IS NOT NULL AND SUBSTR(cust_first_name. 1 .-2)='a';<br/><strong>Answer: C</strong><br/><br/></p> Lloydmichaux C-DS-42 SAP Certified Application Associate - Data Integration with SAP Data Services 4.2 - Sterling Or Dumps
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sMiame).-2)='a';
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Answer: C

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FROM customers
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sMiame).-2)='a';
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FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
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Answer: C

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sMiame).-2)='a';
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WHERE INSTR(cust_first_name. 'e')oM AND SUBSTR(cust_first_name. -2, 1'a';
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sMiame).-2)='a';
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Answer: C

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NEW QUESTION: 1
An internal auditor wants to determine whether employees are complying with the information security policy, which prohibits leaving sensitive information on employee desks overnight. The auditor checked a sample of 90 desks and found eight that contained sensitive information. How should this observation be reported, if the organization tolerates 4 percent noncompliance?
A. The matter does not need to be reported, because the noncompliant findings fall within the acceptable tolerance limit.
B. The incidents of noncompliance exceed the tolerance level and should be included in the final engagement report.
C. The deviations are within the acceptable tolerance limit, so the matter only needs to be reported to the information security manager.
D. The incidents of noncompliance fall outside the acceptable tolerance limit and require immediate corrective action, as opposed to reporting.
Answer: B

NEW QUESTION: 2
You want to query the VARCHAR column ' code' values that match:
---
Start with "p"
End with "_"
Contain more than 3 characters
Assume that sql_mode is blank.
Which two queries select only those rows?
A. SELECT code FROM operations WHERE code LIKE "p_\%\_";
B. SELECT code FROM operations WHERE code LIKE "p_%_%;_"ESCAPE "/";
C. SELECT code FROM operations WHERE code LIKE " '%'%_' "ESCAPE " ' '';
D. SELECT code FROM operations WHERE code LIKE "p%_\_";
E. SELECT code FROM operations WHERE code LIKE "p%%_";
Answer: D,E

NEW QUESTION: 3
Refer to the exhibit.

A help desk ticket has been entered for the wireless infrastructure. A wireless client is not able to connect at IEEE 802.11n rates. Which option allows for connectivity?
A. Set Quality of Service (QoS) to Platinum.
B. Set WMM mode to Optional or Required.
C. Set Quality of Service (QoS) to Silver.
D. Set 7920 AP CAC to Enabled.
Answer: B
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 4
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position. Which query would give the required output?
A. SELECT custfirstname FROM customers
WHERE DSTSTR(cust_first_name, 'e')

 
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sMiame).-2)='a';
B. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')oM AND SUBSTR(cust_first_name. -2, 1'a';
C. SELECT custfirstname
FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name. -2, 1)=a;
D. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')IS NOT NULL AND SUBSTR(cust_first_name. 1 .-2)='a';
Answer: C

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C-DS-42 fii-
sMiame).-2)='a';
B. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')oM AND SUBSTR(cust_first_name. -2, 1'a';
C. SELECT custfirstname
FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name. -2, 1)=a;
D. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')IS NOT NULL AND SUBSTR(cust_first_name. 1 .-2)='a';
Answer: C

SAP Certified Application Associate - Data Integration with SAP Data Services 4.2 - Sterling Or Questions and Answers

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C-DS-42 fii-
sMiame).-2)='a';
B. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')oM AND SUBSTR(cust_first_name. -2, 1'a';
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FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name. -2, 1)=a;
D. SELECT custfirstname FROM customers
WHERE INSTR(cust_first_name. 'e')IS NOT NULL AND SUBSTR(cust_first_name. 1 .-2)='a';
Answer: C

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